olymmath

HMMT November 2017 U5

  • Guts
  • Answer

Define a sequence {an}\left\{a_{n}\right\} by a1=1a_{1}=1 and an=(an−1)!+1a_{n}=\left(a_{n-1}\right)!+1 for every n>1n>1. Find the least nn for which an>1010a_{n}>10^{10}.

Dataset text NuminaMath olympiads. Quoted with source.

Show the answer

6

Solutions

No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

Add a solution

Similar problems

These problems have the most words in common with this statement.

Locator hmnt/2017/u5 · Tag J9Y0FC79R3 · Edit this page on GitHub · Keys: j next, k previous