olymmath

HMMT November 2016 T3

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Complex number ω\omega satisfies ω5=2\omega^{5}=2. Find the sum of all possible values of

ω4+ω3+ω2+ω+1\omega^{4}+\omega^{3}+\omega^{2}+\omega+1

Dataset text NuminaMath olympiads. Quoted with source.

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