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HMMT November 2014 U6

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In the octagon COMPUTER exhibited below, all interior angles are either 90∘90^{\circ} or 270∘270^{\circ} and we have CO=OM=MP=PU=UT=TE=1C O=O M=M P=P U=U T=T E=1.

Point DD (not to scale in the diagram) is selected on segment RER E so that polygons COMPUTED and CDRC D R have the same area. Find DRD R.

Dataset text NuminaMath olympiads. Quoted with source.

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