olymmath

HMMT November 2013 U20

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  • Answer

There exist unique nonnegative integers A,BA, B between 0 and 9 , inclusive, such that

(1001⋅A+110⋅B)2=57,108,249(1001 \cdot A+110 \cdot B)^{2}=57,108,249

Find 10⋅A+B10 \cdot A+B.

Dataset text NuminaMath olympiads. Quoted with source.

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