olymmath

HMMT November 2013 T4

  • Team
  • Answer

Consider triangle ABCA B C with side lengths AB=4,BC=7A B=4, B C=7, and AC=8A C=8. Let MM be the midpoint of segment ABA B, and let NN be the point on the interior of segment ACA C that also lies on the circumcircle of triangle MBCM B C. Compute BNB N.

Dataset text NuminaMath olympiads. Quoted with source.

Show the answer

\frac{\sqrt{210}}{4}

Solutions

No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

Add a solution

Similar problems

These problems have the most words in common with this statement.

Locator hmnt/2013/t4 · Tag WW6V4Y6RT5 · Edit this page on GitHub · Keys: j next, k previous