olymmath

HMMT November 2008 U23

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If xx and yy are real numbers such that (x−4)24+y29=1\frac{(x-4)^{2}}{4}+\frac{y^{2}}{9}=1, find the largest possible value of x24+y29\frac{x^{2}}{4}+\frac{y^{2}}{9}.

Dataset text NuminaMath olympiads. Quoted with source.

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