olymmath

HMMT 2024 T3

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Let ABCA B C be a scalene triangle and MM be the midpoint of BCB C. Let XX be the point such that CX∥ABC X \| A B and ∠AMX=90∘\angle A M X=90^{\circ}. Prove that AMA M bisects ∠BAX\angle B A X.

Dataset text NuminaMath olympiads. Quoted with source.

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