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HMMT 2021 U18

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Triangle ABCA B C has side lengths AB=19,BC=20A B=19, B C=20, and CA=21C A=21. Points XX and YY are selected on sides ABA B and ACA C, respectively, such that AY=XYA Y=X Y and XYX Y is tangent to the incircle of △ABC\triangle A B C. If the length of segment AXA X can be written as ab\frac{a}{b}, where aa and bb are relatively prime positive integers, compute 100a+b100 a+b.

Dataset text NuminaMath olympiads. Quoted with source.

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