olymmath

HMMT 2021 T2

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Let ABCA B C be a right triangle with ∠A=90∘\angle A=90^{\circ}. A circle ω\omega centered on BCB C is tangent to ABA B at DD and ACA C at EE. Let FF and GG be the intersections of ω\omega and BCB C so that FF lies between BB and GG. If lines DGD G and EFE F intersect at XX, show that AX=ADA X=A D.

Dataset text NuminaMath olympiads. Quoted with source.

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A X=A D

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