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HMMT 2021 G10

  • Geometry
  • Answer

Acute triangle ABCA B C has circumcircle Γ\Gamma. Let MM be the midpoint of BCB C. Points PP and QQ lie on Γ\Gamma so that ∠APM=90∘\angle A P M=90^{\circ} and Q≠AQ \neq A lies on line AMA M. Segments PQP Q and BCB C intersect at SS. Suppose that BS=1,CS=3,PQ=8737B S=1, C S=3, P Q=8 \sqrt{\frac{7}{37}}, and the radius of Γ\Gamma is rr. If the sum of all possible values of r2r^{2} can be expressed as ab\frac{a}{b} for relatively prime positive integers aa and bb, compute 100a+b100 a+b.

Dataset text NuminaMath olympiads. Quoted with source.

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