olymmath

HMMT 2020 U32

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Find the smallest real constant α\alpha such that for all positive integers nn and real numbers 0=y0<0=y_{0}< y1<⋯<yny_{1}<\cdots<y_{n}, the following inequality holds:

α∑k=1n(k+1)3/2yk2−yk−12≥∑k=1nk2+3k+3yk. \alpha \sum_{k=1}^{n} \frac{(k+1)^{3 / 2}}{\sqrt{y_{k}^{2}-y_{k-1}^{2}}} \geq \sum_{k=1}^{n} \frac{k^{2}+3 k+3}{y_{k}} \text {. }

Dataset text NuminaMath olympiads. Quoted with source.

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\frac{16 \sqrt{2}}{9}

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