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HMMT 2020 U2

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Let ABCA B C be a triangle and ω\omega be its circumcircle. The point MM is the midpoint of arc BCB C not containing AA on ω\omega and DD is chosen so that DMD M is tangent to ω\omega and is on the same side of AMA M as CC. It is given that AM=ACA M=A C and ∠DMC=38∘\angle D M C=38^{\circ}. Find the measure of angle ∠ACB\angle A C B.

Dataset text NuminaMath olympiads. Quoted with source.

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33^{\circ}

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