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HMMT 2018 U5

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Randall proposes a new temperature system called Felsius temperature with the following conversion between Felsius ∘E{ }^{\circ} E, Celsius ∘C{ }^{\circ} C, and Fahrenheit ∘F{ }^{\circ} F :

∘E=7×∘C5+16=7×∘F−809.{ }^{\circ} E=\frac{7 \times{ }^{\circ} C}{5}+16=\frac{7 \times{ }^{\circ} F-80}{9} .

For example, 0∘C=16∘E0^{\circ} C=16^{\circ} E. Let x,y,zx, y, z be real numbers such that x∘C=x∘E,y∘E=y∘F,z∘C=x^{\circ} C=x^{\circ} E, y^{\circ} E=y^{\circ} F, z^{\circ} C= z∘Fz^{\circ} F. Find x+y+zx+y+z.

Dataset text NuminaMath olympiads. Quoted with source.

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