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HMMT 2018 U12

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△PNR\triangle P N R has side lengths PN=20,NR=18P N=20, N R=18, and PR=19P R=19. Consider a point AA on PN.△NRAP N . \triangle N R A is rotated about RR to △N′RA′\triangle N^{\prime} R A^{\prime} so that R,N′R, N^{\prime}, and PP lie on the same line and AA′A A^{\prime} is perpendicular to PRP R. Find PAAN\frac{P A}{A N}.

Dataset text NuminaMath olympiads. Quoted with source.

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\frac{19}{18}

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