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HMMT 2018 G6

  • Geometry
  • Answer

Let ABCA B C be an equilateral triangle of side length 1. For a real number 0<x<0.50<x<0.5, let A1A_{1} and A2A_{2} be the points on side BCB C such that A1B=A2C=xA_{1} B=A_{2} C=x, and let TA=△AA1A2T_{A}=\triangle A A_{1} A_{2}. Construct triangles TB=△BB1B2T_{B}=\triangle B B_{1} B_{2} and TC=△CC1C2T_{C}=\triangle C C_{1} C_{2} similarly. There exist positive rational numbers b,cb, c such that the region of points inside all three triangles TA,TB,TCT_{A}, T_{B}, T_{C} is a hexagon with area

8x2−bx+c(2−x)(x+1)⋅34\frac{8 x^{2}-b x+c}{(2-x)(x+1)} \cdot \frac{\sqrt{3}}{4}

Find (b,c)(b, c).

Dataset text NuminaMath olympiads. Quoted with source.

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(8,2)

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