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HMMT 2017 A9

  • Algebra and Number Theory
  • Answer

The Fibonacci sequence is defined as follows: F0=0,F1=1F_{0}=0, F_{1}=1, and Fn=Fn−1+Fn−2F_{n}=F_{n-1}+F_{n-2} for all integers n≥2n \geq 2. Find the smallest positive integer mm such that Fm≡0( mod 127)F_{m} \equiv 0(\bmod 127) and Fm+1≡1( mod 127)F_{m+1} \equiv 1(\bmod 127).

Dataset text NuminaMath olympiads. Quoted with source.

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