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HMMT 2017 A6

  • Algebra and Number Theory
  • Answer

A polynomial PP of degree 2015 satisfies the equation P(n)=1n2P(n)=\frac{1}{n^{2}} for n=1,2,…,2016n=1,2, \ldots, 2016. Find ⌊2017P(2017)⌋\lfloor 2017 P(2017)\rfloor.

Dataset text NuminaMath olympiads. Quoted with source.

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