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HMMT 2016 A10

  • Algebra
  • Answer

Let a,ba, b and cc be positive real numbers such that

a2+ab+b2=9b2+bc+c2=52c2+ca+a2=49\begin{aligned} a^{2}+a b+b^{2} & =9 \\ b^{2}+b c+c^{2} & =52 \\ c^{2}+c a+a^{2} & =49 \end{aligned}

Compute the value of 49b2−33bc+9c2a2\frac{49 b^{2}-33 b c+9 c^{2}}{a^{2}}.

Dataset text NuminaMath olympiads. Quoted with source.

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