olymmath

HMMT 2012 S5

  • Team 2
  • Answer

Steph and Jeff each start with the number 4, and Travis is flipping a coin. Every time he flips a heads, Steph replaces her number xx with 2x−12 x-1, and Jeff replaces his number yy with y+8y+8. Every time he flips a tails, Steph replaces her number xx with x+12\frac{x+1}{2}, and Jeff replaces his number yy with y−3y-3. After some (positive) number of coin flips, Steph and Jeff miraculously end up with the same number below 2012. How many times was the coin flipped?

Dataset text NuminaMath olympiads. Quoted with source.

Show the answer

137

Solutions

No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

Add a solution

Similar problems

These problems have the most words in common with this statement.

Locator hmmt/2012/s5 · Tag WGPXX09B1K · Edit this page on GitHub · Keys: j next, k previous