olymmath

HMMT 2012 G4

  • Geometry
  • Answer

There are circles ω1\omega_{1} and ω2\omega_{2}. They intersect in two points, one of which is the point AA. BB lies on ω1\omega_{1} such that ABA B is tangent to ω2\omega_{2}. The tangent to ω1\omega_{1} at BB intersects ω2\omega_{2} at CC and DD, where DD is the closer to BB. ADA D intersects ω1\omega_{1} again at EE. If BD=3B D=3 and CD=13C D=13, find EB/EDE B / E D.

Dataset text NuminaMath olympiads. Quoted with source.

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\frac{4 \sqrt{3}}{3}

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