olymmath

HMMT 2012 C10

  • Combinatorics
  • Answer

Jacob starts with some complex number x0x_{0} other than 0 or 1 . He repeatedly flips a fair coin. If the nth n^{\text {th }} flip lands heads, he lets xn=1−xn−1x_{n}=1-x_{n-1}, and if it lands tails he lets xn=1xn−1x_{n}=\frac{1}{x_{n-1}}. Over all possible choices of x0x_{0}, what are all possible values of the probability that x2012=x0x_{2012}=x_{0} ?

Dataset text NuminaMath olympiads. Quoted with source.

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1, \frac{2^{2011}+1}{3 \cdot 2^{2011}}

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