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HMMT 2011 U29

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Let ABCA B C be a triangle such that AB=AC=182A B=A C=182 and BC=140B C=140. Let X1X_{1} lie on ACA C such that CX1=130C X_{1}=130. Let the line through X1X_{1} perpendicular to BX1B X_{1} at X1X_{1} meet ABA B at X2X_{2}. Define X2,X3,…X_{2}, X_{3}, \ldots, as follows: for nn odd and n≥1n \geq 1, let Xn+1X_{n+1} be the intersection of ABA B with the perpendicular to Xn−1XnX_{n-1} X_{n} through XnX_{n}; for nn even and n≥2n \geq 2, let Xn+1X_{n+1} be the intersection of ACA C with the perpendicular to Xn−1XnX_{n-1} X_{n} through XnX_{n}. Find BX1+X1X2+X2X3+…B X_{1}+X_{1} X_{2}+X_{2} X_{3}+\ldots

Dataset text NuminaMath olympiads. Quoted with source.

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\frac{1106}{5}

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