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HMMT 2011 U11

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Rosencrantz and Guildenstern play a game in which they repeatedly flip a fair coin. Let a1=4a_{1}=4, a2=3a_{2}=3, and an=an−1+an−2a_{n}=a_{n-1}+a_{n-2} for all n≥3n \geq 3. On the nnth flip, if the coin is heads, Rosencrantz pays Guildenstern ana_{n} dollars, and, if the coin is tails, Guildenstern pays Rosencrantz ana_{n} dollars. If play continues for 2010 turns, what is the probability that Rosencrantz ends up with more money than he started with?

Dataset text NuminaMath olympiads. Quoted with source.

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\frac{1}{2}-\frac{1}{2^{1341}}

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