olymmath

HMMT 2011 S9

  • Team 2

Let ABCA B C be a non-isosceles, non-right triangle, let ω\omega be its circumcircle, and let OO be its circumcenter. Let MM be the midpoint of segment BCB C. Let the tangents to ω\omega at BB and CC intersect at XX. Prove that ∠OAM=∠OXA\angle O A M=\angle O X A. (Hint: use SAS similarity).

Dataset text NuminaMath olympiads. Quoted with source.

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