olymmath

HMMT 2010 U22

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You are the general of an army. You and the opposing general both have an equal number of troops to distribute among three battlefields. Whoever has more troops on a battlefield always wins (you win ties). An order is an ordered triple of non-negative real numbers (x,y,z)(x, y, z) such that x+y+z=1x+y+z=1, and corresponds to sending a fraction xx of the troops to the first field, yy to the second, and zz to the third. Suppose that you give the order (14,14,12)\left(\frac{1}{4}, \frac{1}{4}, \frac{1}{2}\right) and that the other general issues an order chosen uniformly at random from all possible orders. What is the probability that you win two out of the three battles?

Dataset text NuminaMath olympiads. Quoted with source.

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\frac{5}{8}

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