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HMMT 2009 E10

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A kite is a quadrilateral whose diagonals are perpendicular. Let kite ABCDA B C D be such that ∠B=\angle B= ∠D=90∘\angle D=90^{\circ}. Let MM and NN be the points of tangency of the incircle of ABCDA B C D to ABA B and BCB C respectively. Let ω\omega be the circle centered at CC and tangent to ABA B and ADA D. Construct another kite AB′C′D′A B^{\prime} C^{\prime} D^{\prime} that is similar to ABCDA B C D and whose incircle is ω\omega. Let N′N^{\prime} be the point of tangency of B′C′B^{\prime} C^{\prime} to ω\omega. If MN′∥ACM N^{\prime} \| A C, then what is the ratio of AB:BCA B: B C ?

Dataset text NuminaMath olympiads. Quoted with source.

Also HMMT 2009 G4.

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\frac{1+\sqrt{5}}{2}

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