olymmath

HMMT 2007 S7

  • Team 2
  • Answer

Three positive reals x,yx, y, and zz are such that

x2+2(y−1)(z−1)=85y2+2(z−1)(x−1)=84z2+2(x−1)(y−1)=89\begin{aligned} x^{2}+2(y-1)(z-1) & =85 \\ y^{2}+2(z-1)(x-1) & =84 \\ z^{2}+2(x-1)(y-1) & =89 \end{aligned}

Compute x+y+zx+y+z.

Dataset text NuminaMath olympiads. Quoted with source.

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