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HMMT 2007 G6

  • Geometry
  • Answer

Triangle ABCA B C has ∠A=90∘\angle A=90^{\circ}, side BC=25,AB>ACB C=25, A B>A C, and area 150. Circle ω\omega is inscribed in ABCA B C, with MM its point of tangency on ACA C. Line BMB M meets ω\omega a second time at point LL. Find the length of segment BLB L.

Dataset text NuminaMath olympiads. Quoted with source.

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\frac{45\sqrt{17}}{17}

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