olymmath

HMMT 2006 G5

  • Geometry
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Triangle ABCA B C has side lengths AB=25,BC=1A B=2 \sqrt{5}, B C=1, and CA=5C A=5. Point DD is on side ACA C such that CD=1C D=1, and FF is a point such that BF=2B F=2 and CF=3C F=3. Let EE be the intersection of lines ABA B and DFD F. Find the area of CDEBC D E B.

Dataset text NuminaMath olympiads. Quoted with source.

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\frac{22}{35}

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