olymmath

HMMT 2005 U22

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Find

{ln⁡(1+e)}+{ln⁡(1+e2)}+{ln⁡(1+e4)}+{ln⁡(1+e8)}+⋯ ,\{\ln (1+e)\}+\left\{\ln \left(1+e^{2}\right)\right\}+\left\{\ln \left(1+e^{4}\right)\right\}+\left\{\ln \left(1+e^{8}\right)\right\}+\cdots,

where {x}=x−⌊x⌋\{x\}=x-\lfloor x\rfloor denotes the fractional part of xx.

Dataset text NuminaMath olympiads. Quoted with source.

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1-\ln (e-1)

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