olymmath

HMMT 2003 G10

  • Geometry
  • Answer

Convex quadrilateral MATHM A T H is given with HM/MT=3/4H M / M T=3 / 4, and ∠ATM=∠MAT=\angle A T M=\angle M A T= ∠AHM=60∘.N\angle A H M=60^{\circ} . N is the midpoint of MAM A, and OO is a point on THT H such that lines MT,AH,NOM T, A H, N O are concurrent. Find the ratio HO/OTH O / O T.

Dataset text NuminaMath olympiads. Quoted with source.

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\frac{9}{16}

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