olymmath

HMMT 2003 A6

  • Algebra
  • Answer

Let a1=1a_{1}=1, and let an=⌊n3/an−1⌋a_{n}=\left\lfloor n^{3} / a_{n-1}\right\rfloor for n>1n>1. Determine the value of a999a_{999}.

Dataset text NuminaMath olympiads. Quoted with source.

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999

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