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HMMT 2003 A2

  • Algebra
  • Answer

Compute tan⁡2(20∘)−sin⁡2(20∘)tan⁡2(20∘)sin⁡2(20∘)\frac{\tan ^{2}\left(20^{\circ}\right)-\sin ^{2}\left(20^{\circ}\right)}{\tan ^{2}\left(20^{\circ}\right) \sin ^{2}\left(20^{\circ}\right)}.

Dataset text NuminaMath olympiads. Quoted with source.

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