olymmath

HMMT 1999 A10

  • Algebra
  • Answer

Pyramid EARLYE A R L Y is placed in (x,y,z)(x, y, z) coordinates so that E=(10,10,0),A=(10,−10,0),R=E=(10,10,0), A=(10,-10,0), R= (−10,−10,0),L=(−10,10,0)(-10,-10,0), L=(-10,10,0), and Y=(0,0,10)Y=(0,0,10). Tunnels are drilled through the pyramid in such a way that one can move from (x,y,z)(x, y, z) to any of the 9 points (x,y,z−1),(x±1,y,z−1)(x, y, z-1),(x \pm 1, y, z-1), (x,y±1,z−1),(x±1,y±1,z−1)(x, y \pm 1, z-1),(x \pm 1, y \pm 1, z-1). Sean starts at YY and moves randomly down to the base of the pyramid, choosing each of the possible paths with probability 19\frac{1}{9} each time. What is the probability that he ends up at the point (8,9,0)(8,9,0) ?

Dataset text NuminaMath olympiads. Quoted with source.

Show the answer

\frac{550}{9^{10}}

Solutions

No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

Add a solution

Similar problems

These problems have the most words in common with this statement.

Locator hmmt/1999/a10 · Tag 77QX462WWR · Edit this page on GitHub · Keys: j next, k previous