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HMIC 2020 Problem 4

    Let Ck=1k+1(2kk)C_{k}=\frac{1}{k+1}\binom{2 k}{k} denote the kth k^{\text {th }} Catalan number and pp be an odd prime. Prove that exactly half of the numbers in the set

    {∑k=1p−1Cknk∣n∈{1,2,…,p−1}}\left\{\sum_{k=1}^{p-1} C_{k} n^{k} \mid n \in\{1,2, \ldots, p-1\}\right\}

    are divisible by pp.

    Dataset text NuminaMath olympiads. Quoted with source.

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