olymmath

OFM 2021

Olympiade Francophone de Mathématiques 2021.

Junior

J1

  • Junior

Let RR and SS be the numbers defined by R=12×34×56×⋯×223224 and S=23×45×67×⋯×224225.R = \dfrac{1}{2} \times \dfrac{3}{4} \times \dfrac{5}{6} \times \cdots \times \dfrac{223}{224} \text{ and } S = \dfrac{2}{3} \times \dfrac{4}{5} \times \dfrac{6}{7} \times \cdots \times \dfrac{224}{225}.Prove that R<115<SR < \dfrac{1}{15} < S .

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J2

  • Junior

Evariste has drawn twelve triangles as follows, so that two consecutive triangles share exactly one edge. Image Sophie colors every triangle side in red, green or blue. Among the 3243^{24} possible colorings, how many have the property that every triangle has one edge of each color?

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J3

  • Junior

Every point in the plane was colored in red or blue. Prove that one the two following statements is true: ∙\bullet there exist two red points at distance 11 from each other; ∙\bullet there exist four blue points B1B_1 , B2B_2 , B3B_3 , B4B_4 such that the points BiB_i and BjB_j are at distance ∣i−j∣|i - j| from each other, for all integers ii and jj such as 1≤i≤41 \le i \le 4 and 1≤j≤41 \le j \le 4 .

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J4

  • Junior

Let N⩾1\mathbb{N}_{\geqslant 1} be the set of positive integers. Find all functions f ⁣:N⩾1→N⩾1f \colon \mathbb{N}_{\geqslant 1} \to \mathbb{N}_{\geqslant 1} such that, for all positive integers mm and nn : GCD(f(m),n)+LCM(m,f(n))=GCD(m,f(n))+LCM(f(m),n).\mathrm{GCD}\left(f(m),n\right) + \mathrm{LCM}\left(m,f(n)\right) = \mathrm{GCD}\left(m,f(n)\right) + \mathrm{LCM}\left(f(m),n\right).

Note: if aa and bb are positive integers, GCD(a,b)\mathrm{GCD}(a,b) is the largest positive integer that divides both aa and bb , and LCM(a,b)\mathrm{LCM}(a,b) is the smallest positive integer that is a multiple of both aa and bb .

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Senior

S1

  • Senior

Let a1,a2,a3,…a_1,a_2,a_3,\ldots and b1,b2,b3,…b_1,b_2,b_3,\ldots be positive integers such that an+2=an+an+1a_{n+2} = a_n + a_{n+1} and bn+2=bn+bn+1b_{n+2} = b_n + b_{n+1} for all n≥1n \ge 1 . Assume that ana_n divides bnb_n for infinitely many values of nn . Prove that there exists an integer cc such that bn=canb_n = c a_n for all n≥1n \ge 1 .

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S2

  • Senior

Albert and Beatrice play a game. 20212021 stones lie on a table. Starting with Albert, they alternatively remove stones from the table, while obeying the following rule. At the nn -th turn, the active player (Albert if nn is odd, Beatrice if nn is even) can remove from 11 to nn stones. Thus, Albert first removes 11 stone; then, Beatrice can remove 11 or 22 stones, as she wishes; then, Albert can remove from 11 to 33 stones, and so on. The player who removes the last stone on the table loses, and the other one wins. Which player has a strategy to win regardless of the other player's moves?

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S3

  • Senior

Let ABCDABCD be a square with incircle Γ\Gamma . Let MM be the midpoint of the segment [CD][CD] . Let P≠BP \neq B be a point on the segment [AB][AB] . Let E≠ME \neq M be the point on Γ\Gamma such that (DP)(DP) and (EM)(EM) are parallel. The lines (CP)(CP) and (AD)(AD) meet each other at FF . Prove that the line (EF)(EF) is tangent to Γ\Gamma

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S4

  • Senior

Let N≥1\mathbb{N}_{\ge 1} be the set of positive integers. Find all functions f ⁣:N≥1→N≥1f \colon \mathbb{N}_{\ge 1} \to \mathbb{N}_{\ge 1} such that, for all positive integers mm and nn :

(a) n=(f(2n)−f(n))(2f(n)−f(2n))n = \left(f(2n)-f(n)\right)\left(2 f(n) - f(2n)\right) , (b) f(m)f(n)−f(mn)=(f(2m)−f(m))(2f(n)−f(2n))+(f(2n)−f(n))(2f(m)−f(2m))f(m)f(n) - f(mn) = \left(f(2m)-f(m)\right)\left(2 f(n) - f(2n)\right) + \left(f(2n)-f(n)\right)\left(2 f(m) - f(2m)\right) , (c) m−nm-n divides f(2m)−f(2n)f(2m)-f(2n) if mm and nn are distinct odd prime numbers.

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