olymmath

OME 2023

Spanish Mathematical Olympiad 2023.

Other problems

Problem 1

A 3×3×33\times 3\times 3 cube is made of 27 unit cube pieces. Each piece contains a lamp, which can be on or off. Every time a piece is pressed (the center piece cannot be pressed), the state of that piece and the pieces that share a face with it changes. Initially all lamps are off. Determine which of the following states are achievable: (1) All lamps are on. (2) All lamps are on except the central one. (3) Only the central lamp is on.

Problem 2

Let ABCABC be an acute scalene triangle with incenter II and orthocenter HH . Let MM be the midpoint of ABAB . On the line AHAH we consider points DD and EE , such that the line MDMD is parallel to CICI and MEME is perpendicular to CICI . Prove that AE=DHAE=DH .

Problem 3

Find all quadruples (a,b,c,d)(a,b,c,d) of positive integers satisfying that a2+b2=c2+d2a^2+b^2=c^2+d^2 and such that ac+bdac+bd divides a2+b2a^2+b^2 .

Problem 4

Let x1≤x2≤x3≤x4x_1\leq x_2\leq x_3\leq x_4 be real numbers. Prove that there exist polynomials of degree two P(x)P(x) and Q(x)Q(x) with real coefficients such that x1x_1 , x2x_2 , x3x_3 and x4x_4 are the roots of P(Q(x))P(Q(x)) if and only if x1+x4=x2+x3x_1+x_4=x_2+x_3 .

Problem 5

We have a row of 203 cells. Initially the leftmost cell contains 203 tokens, and the rest are empty. On each move we can do one of the following: 1)Take one token, and move it to an adjacent cell (left or right). 2)Take exactly 20 tokens from the same cell, and move them all to an adjacent cell (all left or all right). After 2023 moves each cell contains one token. Prove that there exists a token that moved left at least nine times.

Problem 6

In an acute scalene triangle ABCABC with incenter II , the line AIAI intersects the circumcircle again at DD , and let JJ be a point such that DD is the midpoint of IJIJ . Consider points EE and FF on line BCBC such that IEIE and JFJF are perpendicular to AIAI . Consider points GG on AEAE and HH on AFAF such that IGIG and JHJH are perpendicular to AEAE and AFAF , respectively. Prove that BG=CHBG=CH .