Home Competitions OME 2017 Problem 3
Let p p p be an odd prime and S q = 1 2 ∗ 3 ∗ 4 + 1 5 ∗ 6 ∗ 7 + . . . + 1 q ( q + 1 ) ( q + 2 ) S_{q} = \frac{1}{2*3*4} + \frac{1}{5*6*7} + ... + \frac{1}{q(q+1)(q+2)} S q = 2 ∗ 3 ∗ 4 1 + 5 ∗ 6 ∗ 7 1 + ... + q ( q + 1 ) ( q + 2 ) 1 , where q = 3 p − 5 2 q = \frac{3p-5}{2} q = 2 3 p − 5 .
We write 1 2 − 2 S q \frac{1}{2}-2S_{q} 2 1 − 2 S q in the form m n \frac{m}{n} n m , where m m m and n n n are integers. Prove that m ≡ n ( m o d p ) m \equiv n (mod p) m ≡ n ( m o d p )
Dataset text AI-MO AoPS . Quoted with source.
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