olymmath

OME 2002 Problem 3

    The function gg is defined about the natural numbers and satisfies the following conditions: g(2)=1g(2) = 1 g(2n)=g(n)g(2n) = g(n) g(2n+1)=g(2n)+1.g(2n+1) = g(2n) +1. Where nn is a natural number such that 1≤n≤20021 \leq n \leq 2002 .

    Find the maximum value MM of g(n).g(n). Also, calculate how many values of nn satisfy the condition of g(n)=M.g(n) = M.

    Dataset text AI-MO AoPS. Quoted with source.

    Solutions

    No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

    Add a solution

    Similar problems

    These problems have the most words in common with this statement.

    Locator es-ome/2002/p3 · Tag 99YCW8DD76 · Edit this page on GitHub · Keys: j next, k previous