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ELMO SL 2017 G4

    Let ABCABC be an acute triangle with incenter II and circumcircle ω\omega . Suppose a circle ωB\omega_B is tangent to BA,BCBA,BC , and internally tangent to ω\omega at B1B_1 , while a circle ωC\omega_C is tangent to CA,CBCA, CB , and internally tangent to ω\omega at C1C_1 . If B2,C2B_2, C_2 are the points opposite to B,CB,C on ω\omega , respectively, and XX denotes the intersection of B1C2,B2C1B_1C_2, B_2C_1 , prove that XA=XIXA=XI .

    [i]Proposed by Vincent Huang and Nathan Weckwerth

    Dataset text AI-MO AoPS. Quoted with source.

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