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DK-GEORGMOHR 2024 Problem 5

    Let 0<x1<x2<...<x2024=10 < x_1 < x_2 < ... < x_{2024} = 1 be real numbers. A colouring of these numbers consists of painting 10121012 of the numbers red and the remaining 10121012 numbers blue. The red numbers are denoted in ascending order r1<...<r1012r_1 < ... < r_{1012} , and the blue numbers in ascending order b1<...<b1012b_1 <...< b_{1012} . Two examples of colourings are: x1,...,x1012⏟r1,...,r1012,x1013,...,x2024⏟b1,...,b1012  andx1⏟r1,x2⏟b1,x3⏟r2,x4⏟b2,...,x2023⏟r1012,x2024⏟r1013.\underbrace{x_1, . . . , x_{1012}}_{r_1,...,r_{1012}},\underbrace{x_{1013}, ... , x_{2024}}_{b_1,...,b_{1012}} \,\, and \underbrace{x_1}_{r_1}, \underbrace{x_2}_{b_1},\underbrace{x_3}_{r_2},\underbrace{x_4}_{b_2},...,\underbrace{x_{2023}}_{r_{1012}} ,\underbrace{x_{2024}}_{r_{1013}}. For any colouring one considers the quantity S=r1b1+r2(b2−b1)+r3(b3−b2)+...+r1012(b1012−b1011).S = r_1b_1 + r_2(b_2-b_1) + r_3(b_3 - b_2) +...+ r_{1012}(b_{1012} - b_{1011}). a) Prove that one may choose the numbers x1,..,x2024x_1, .., x_{2024} such that any colouring satisfies S<12S < \frac12 . b) Prove that no matter how the numbers x1,..,x2024x_1, .., x_{2024} are chosen, there exists a colouring so that S>x20232S > \frac{x_{2023}}{2} .

    Dataset text AI-MO AoPS. Quoted with source.

    Official text: Georg Mohr Contest 2024 official paper, page 1.

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