olymmath

CZ-SK-MO 2011

Czech-Slovak Mathematical Olympiad 2011.

Other problems

Problem 1

In a certain triangle ABCABC , there are points KK and MM on sides ABAB and ACAC , respectively, such that if LL is the intersection of MBMB and KCKC , then both AKLMAKLM and KBCMKBCM are cyclic quadrilaterals with the same size circumcircles. Find the measures of the interior angles of triangle ABCABC .

Problem 2

Find all triples (p,q,r)(p, q, r) of prime numbers for which (p+1)(q+2)(r+3)=4pqr.(p+1)(q+2)(r+3)=4pqr.

Problem 3

Suppose that xx , yy , zz are real numbers satisfying x+y+z=12,andx2+y2+z2=54.x+y+z=12, \text{and} x^2+y^2+z^2=54. Prove that:list Each of the numbers xyxy , yzyz , zxzx is at least 99 , but at most 2525 . (b) One of the numbers xx , yy , zz is at most 33 , and another one is at least 55 .[/list]

Problem 4

Consider a quadratic polynomial ax2+bx+cax^2+bx+c with real coefficients satisfying a≥2a\ge 2 , b≥2b\ge 2 , c≥2c\ge 2 . Adam and Boris play the following game. They alternately take turns with Adam first. On Adam's turn, he can choose one of the polynomial's coefficients and replace it with the sum of the other two coefficients. On Boris's turn, he can choose one of the polynomial's coefficients and replace it with the product of the other two coefficients. The winner is the player who first produces a polynomial with two distinct real roots. Depending on the values of aa , bb and cc , determine who has a winning strategy.

Problem 5

In acute triangle ABC, which is not equilateral, let PP denote the foot of the altitude from CC to side ABAB ; let HH denote the orthocenter; let OO denote the circumcenter; let DD denote the intersection of line COCO with ABAB ; and let EE denote the midpoint of CDCD . Prove that line EPEP passes through the midpoint of OHOH .

Problem 6

Let R+\mathbb{R}^+ denote the set of positive real numbers. Find all functions f:R+→R+f:\mathbb{R}^+\to\mathbb{R}^+ such that for any x,y∈R+x,y\in\mathbb{R}^+ , we have f(x)f(y)=f(y)f(xf(y))+1xy.f(x)f(y)=f(y)f\Big(xf(y)\Big)+\frac{1}{xy}.