CZ-SK-MO 1987 Problem 2

Given a prime $p>3$ and an odd integer $n>0$ , show that the equation $$xyz=p^n(x+y+z)$$ has at least $3(n+1)$ different solutions up to symmetry. (That is, if $(x',y',z')$ is a solution and $(x'',y'',z'')$ is a permutation of the previous, they are considered to be the same solution.)