olymmath

CONO-SUR 1995

Cono Sur Mathematical Olympiad 1995.

Other problems

Problem 1

Find a number with 33 digits, knowing that the sum of its digits is 99 , their product is 2424 and also the number read from right to left is 2738\frac{27}{38} of the original.

Problem 2

There are ten points marked on a circumference, numbered from 11 to 1010 and join all points with segments. I color the segments, with red someones and others with blue. Without changing the colors of the segments, renumber all the points from the 11 to the 1010 . Will be possible to color the segments and to renumber the points so that those numbers that were jointed with red are jointed now with blue and the numbers that were jointed with blue they are jointed now with red?

Problem 3

Let ABCDABCD be a rectangle with: AB=aAB=a , BC=bBC=b . Inside the rectangle we have to exteriorly tangents circles such that one is tangent to the sides ABAB and ADAD ,the other is tangent to the sides CBCB and CDCD .

  1. Find the distance between the centers of the circles(using aa and bb ).
  2. When the radiums of both circles change the tangency point between both of them changes, and describes a locus. Find that locus.

Attachments:

con6_1.gif

Problem 5

The semicircle with centre OO and the diameter ACAC is divided in two arcs ABAB and BCBC with ratio 1:31: 3 . MM is the midpoint of the radium OCOC . Let TT be the point of arc BCBC such that the area of the cuadrylateral OBTMOBTM is maximum. Find such area in fuction of the radium.

Problem 6

Let nn be a natural number and f(n)=2n−1995⌊n1000⌋f(n) = 2n - 1995 \lfloor \frac{n}{1000} \rfloor ( ⌊\lfloor ⌋\rfloor denotes the floor function).

  1. Show that if for some integer rr : f(f(f...f(n)...))=1995f(f(f...f(n)...))=1995 (where the function ff is applied rr times), then nn is multiple of 19951995 .

  2. Show that if nn is multiple of 1995, then there exists r such that: f(f(f...f(n)...))=1995f(f(f...f(n)...))=1995 (where the function ff is applied rr times). Determine rr if n=1995.500=997500n=1995.500=997500