olymmath

CMO 2019 Problem 3

  • Day 1

Let OO be the circumcenter of △ABC\triangle ABC ( AB<ACAB<AC ), and DD be a point on the internal angle bisector of ∠BAC\angle BAC . Point EE lies on BCBC , satisfying OE∥ADOE\parallel AD , DE⊥BCDE\perp BC . Point KK lies on EBEB extended such that EK=EAEK=EA . The circumcircle of △ADK\triangle ADK meets BCBC at P≠KP\neq K , and meets the circumcircle of △ABC\triangle ABC at Q≠AQ\neq A . Prove that PQPQ is tangent to the circumcircle of △ABC\triangle ABC .

Dataset text AI-MO AoPS. Quoted with source.

Solutions

No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

Add a solution

Similar problems

These problems have the most words in common with this statement.

Locator cn-mo/2019/p3 · Tag EN1HB6WKER · Edit this page on GitHub · Keys: j next, k previous