olymmath

CMO 1997 Problem 3

  • Day 1

Prove that there are infinitely many natural numbers nn such that we can divide 1,2,…,3n1,2,\ldots ,3n into three sequences (an),(bn)(a_n),(b_n) and (cn)(c_n) , with nn terms in each, satisfying the following conditions: i) a1+b1+c1=a2+b2+c2=…=an+bn+cna_1+b_1+c_1= a_2+b_2+c_2=\ldots =a_n+b_n+c_n and a1+b1+c1a_1+b_1+c_1 is divisible by 66 ; ii) a1+a2+…+an=b1+b2+…+bn=c1+c2+…+cn,a_1+a_2+\ldots +a_n= b_1+b_2+\ldots +b_n=c_1+c_2+\ldots +c_n, and a1+a2+…+ana_1+a_2+\ldots +a_n is divisible by 66 .

Dataset text AI-MO AoPS. Quoted with source.

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