olymmath

CMO 1994

Chinese Mathematical Olympiad 1994.

Day 1

Problem 1

  • Day 1

Let ABCDABCD be a trapezoid with AB∥CDAB\parallel CD . Points E,FE,F lie on segments AB,CDAB,CD respectively. Segments CE,BFCE,BF meet at HH , and segments ED,AFED,AF meet at GG . Show that SEHFG≤14SABCDS_{EHFG}\le \dfrac{1}{4}S_{ABCD} . Determine, with proof, if the conclusion still holds when ABCDABCD is just any convex quadrilateral.

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Problem 2

  • Day 1

There are mm pieces of candy held in nn trays( n,m≥4n,m\ge 4 ). An operation is defined as follow: take out one piece of candy from any two trays respectively, then put them in a third tray. Determine, with proof, if we can move all candies to a single tray by finite operations.

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Problem 3

  • Day 1

Find all functions f:[1,∞)→[1,∞)f:[1,\infty )\rightarrow [1,\infty) satisfying the following conditions: (1) f(x)≤2(x+1)f(x)\le 2(x+1) ; (2) f(x+1)=1x[(f(x))2−1]f(x+1)=\dfrac{1}{x}[(f(x))^2-1] .

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Day 2

Problem 4

  • Day 2

Let f(z)=c0zn+c1zn−1+c2zn−2+⋯+cn−1z+cnf(z)=c_0z^n+c_1z^{n-1}+ c_2z^{n-2}+\cdots +c_{n-1}z+c_n be a polynomial with complex coefficients. Prove that there exists a complex number z0z_0 such that ∣f(z0)∣≥∣c0∣+∣cn∣|f(z_0)|\ge |c_0|+|c_n| , where ∣z0∣≤1|z_0|\le 1 .

Answer, solutions and source

Problem 5

  • Day 2

For arbitrary natural number nn , prove that ∑k=0nCnk2kCn−k[(n−k)/2]=C2n+1n\sum^n_{k=0}C^k_n2^kC^{[(n-k)/2]}_{n-k}=C^n_{2n+1} , where C00=1C^0_0=1 and [n−k2][\dfrac{n-k}{2}] denotes the integer part of n−k2\dfrac{n-k}{2} .

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Problem 6

  • Day 2

Let MM be a point which has coordinates (p×1994,7p×1994)(p\times 1994,7p\times 1994) in the Cartesian plane ( pp is a prime). Find the number of right-triangles satisfying the following conditions: (1) all vertexes of the triangle are lattice points, moreover MM is on the right-angled corner of the triangle; (2) the origin ( 0,00,0 ) is the incenter of the triangle.

Answer, solutions and source