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CN-LEAGUE 2021 Problem 2

    In △ABC\triangle ABC , point MM is the middle point of ACAC . MD//ABMD//AB and meet the tangent of AA to ⊙(ABC)\odot(ABC) at point DD . Point EE is in ADAD and point AA is the middle point of DEDE . {P}=⊙(ABE)∩AC,{Q}=⊙(ADP)∩DM\{P\}=\odot(ABE)\cap AC,\{Q\}=\odot(ADP)\cap DM . Prove that ∠QCB=∠BAC\angle QCB=\angle BAC . Image

    Dataset text AI-MO AoPS. Quoted with source.

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