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CGMO 2016 Problem 7

    In acute triangle ABC,AB<ACABC, AB<AC , II is its incenter, DD is the foot of perpendicular from II to BCBC , altitude AHAH meets BI,CIBI,CI at P,QP,Q respectively. Let OO be the circumcenter of △IPQ\triangle IPQ , extend AOAO to meet BCBC at LL . Circumcircle of △AIL\triangle AIL meets BCBC again at NN . Prove that BDCD=BNCN\frac{BD}{CD}=\frac{BN}{CN} .

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    Dataset text AI-MO AoPS. Quoted with source.

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