olymmath

CIIM 2012 Problem 6

  • Day 2

Let n≥2n \geq 2 and p(x)=xn+an−1xn−1+⋯+a1x+a0p(x) = x^n + a_{n-1} x^{n-1} + \cdots + a_1 x + a_0 a polynomial with real coefficients. Show that if there exists a positive integer kk such that (x−1)k+1(x-1)^{k+1} divides p(x)p(x) then ∑j=0n−1∣aj∣>1+2k2n.\sum_{j=0}^{n-1}|a_j| > 1 +\frac{2k^2}{n}.

Dataset text AI-MO AoPS. Quoted with source.

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